I discovered that programming in Point-Free Style can be addictive! Today, I wrote two perverse functions using PFS before discovering I had spent almost two hours just two add two lines to my code!!!
Here's the one of the two:
foo = uncurry (.) . (map . second . drop . length &&& (filter . (flip $ flip isPrefixOf . snd)))
Sorry if it didn't fit in your screen. I used the name foo purposedly: can you imagine what this function does?
If you can't come up with a solution in less than 1 minute, the above code is a failure as it means nothing to you (i.e. its meaning is not apparent).
Try with the following version:
foo p [] = []
foo p ( (k,l):os ) | p `isPrefixOf` l = (k,take (length p) l) : foo p os
| otherwise = foo p os
Sorry for the bad layout.
It took two hours to me to figure out how and where to put all those . and $ in the first version but it was fun, just like winning a game.
On the other hand, I wrote the second version as I was writing this post. I think the reason why I write PFS code much much slower lies both in my lack of knowledge of PFS programming and my way of reasoning about programs.
Nevertheless, PFS is appealing to me because I'm used to write shell scripts to automate things on the systems I manage: PFS is all about composing and piping functions, mostly like you compose and pipe shell programs.
I wonder if I'll be able to guess the meaning of the PFS functions I wrote after some months: we'll see.
As a side note, I noticed that the following pattern is coming up rather often when coding in FPS:
goo = uncurry g . (foo &&& bar)
which means:
goo i = foo i `g` bar i
So, I wonder whether the following combinator would help to making FPS code more readable:
f `interspersedBy` g = uncurry g . f
So, the above snippet would become:
goo = (foo &&& bar) `interspersedBy` g
December 05, 2007
December 04, 2007
Arrows first encounter
UPDATE: My post appeared on Reddit's programming feed. Thank you! Also, my post's title should've been "Point-free programming style first encounter", but I'm too lazy to change it ^_^
I was really busy lately so no post around for a while. Surprisingly, I wasn't busy wrinting code but actually thinking about the problem: this is feasible in Haskell as the code is more concise and the typing system keeps you from doing stupid design mistakes (or at least make them appear earlier than in other programming language).
Now, done with the ritual Haskell-awe prologue, here my post for today.
Lately, I've been working to a program manipulating objects which turned out to be monomials, which I represented as a pair of (Double,[Int]), i.e.:
(4.0,[1,2,-1,-2]) -> 4.0 x(1,1) x(2,2) x(3,-1) x(4,-2)
where x(i,j) are unknowns indexed by a pair. Since I assume that the first component of the unknowns' pairs will be the sequence 1,2,3,... I only need to specify the second component. I know, it's kinda weird, but it has to do with my domain problem which is related to finite difference operators for PDE.
Now I want to define a "product" operator which works like this:
(k,[b,c,d]) * (h,[e,f,g]) = (k*h,[a+e, c+f, d+g])
I can define this like follows:
prod (k,ll) (h,rl) = (k*h, zipWith (+) ll rl)
This is perfectly correct and good as it's very expressive.
Now, I want to apply the same function monadically to list arguments, i.e.:
prod :: [(Double,[Int])] -> [(Double,[(Double,[Int])] -> [(Double,[Int])]
To do this, I'll use liftM2 which take a function of two arguments and applies it to every pair formed taking an element from the first list and an element from the second. So:
prodM = liftM2 prod
But I'll never use prod by itself, so let's put this in a lambda abstraction and rename prodM to prod:
prod = liftM2 $ \(k,ll) (h,rl) -> (k*h, zipWith (+) ll rl)
Again, this is correct but my Haskell soul is becoming more strict and such a formulation sounds bad to me (I could've felt perfectly right with some month ago). I don't like lambdas when used this way, I see as an intrusive element in the perfect world of function combinators/operators (and liftM2 is such a combinator). More, I had to specify that prod requires two tuples while it'd be neat if the compiler could infere this automatically: I see this as code replication issue.
The solution to this dilemma is using point-free style programming. I'll abuse arrow combinators a bit. Specifically, there's the (***) operator which takes two function f and g and applies them to a tuple:
(f *** g) (a,b) = (f a, g b)
What if I need to combine two tuples using two separate binary operators? I.e.:
(f ***' g) (a,b) (c,d) = (f a c, g b d)
Arrows module doesn't provides such a combinator but we could build one. First, if we combine f and g using (***), we get a pair of two functions as f and g are partially evaluated. What we need now is to interpose (***) between these two functions. How to do this? Simple, we just need to uncurry (***). So, now:
(f ***' g) = uncurry (***) . (f *** g)
and we're done as f ***' g returns a function taking two tuples and apply f and g separately to each component. This is good as we can rewrite prod as:
prod = liftM2 $ uncurry (***) . ((*) *** (zipWith (+)))
which is essentially a smart combination of functions. Notice that no arguments of prod has been specified: this is where point-free programming style really lies. Changing the way prod is written will change the type of its arguments, in single place, without requiring you to rewrite them in two places (i.e. the argument list).
I was really busy lately so no post around for a while. Surprisingly, I wasn't busy wrinting code but actually thinking about the problem: this is feasible in Haskell as the code is more concise and the typing system keeps you from doing stupid design mistakes (or at least make them appear earlier than in other programming language).
Now, done with the ritual Haskell-awe prologue, here my post for today.
Lately, I've been working to a program manipulating objects which turned out to be monomials, which I represented as a pair of (Double,[Int]), i.e.:
(4.0,[1,2,-1,-2]) -> 4.0 x(1,1) x(2,2) x(3,-1) x(4,-2)
where x(i,j) are unknowns indexed by a pair. Since I assume that the first component of the unknowns' pairs will be the sequence 1,2,3,... I only need to specify the second component. I know, it's kinda weird, but it has to do with my domain problem which is related to finite difference operators for PDE.
Now I want to define a "product" operator which works like this:
(k,[b,c,d]) * (h,[e,f,g]) = (k*h,[a+e, c+f, d+g])
I can define this like follows:
prod (k,ll) (h,rl) = (k*h, zipWith (+) ll rl)
This is perfectly correct and good as it's very expressive.
Now, I want to apply the same function monadically to list arguments, i.e.:
prod :: [(Double,[Int])] -> [(Double,[(Double,[Int])] -> [(Double,[Int])]
To do this, I'll use liftM2 which take a function of two arguments and applies it to every pair formed taking an element from the first list and an element from the second. So:
prodM = liftM2 prod
But I'll never use prod by itself, so let's put this in a lambda abstraction and rename prodM to prod:
prod = liftM2 $ \(k,ll) (h,rl) -> (k*h, zipWith (+) ll rl)
Again, this is correct but my Haskell soul is becoming more strict and such a formulation sounds bad to me (I could've felt perfectly right with some month ago). I don't like lambdas when used this way, I see as an intrusive element in the perfect world of function combinators/operators (and liftM2 is such a combinator). More, I had to specify that prod requires two tuples while it'd be neat if the compiler could infere this automatically: I see this as code replication issue.
The solution to this dilemma is using point-free style programming. I'll abuse arrow combinators a bit. Specifically, there's the (***) operator which takes two function f and g and applies them to a tuple:
(f *** g) (a,b) = (f a, g b)
What if I need to combine two tuples using two separate binary operators? I.e.:
(f ***' g) (a,b) (c,d) = (f a c, g b d)
Arrows module doesn't provides such a combinator but we could build one. First, if we combine f and g using (***), we get a pair of two functions as f and g are partially evaluated. What we need now is to interpose (***) between these two functions. How to do this? Simple, we just need to uncurry (***). So, now:
(f ***' g) = uncurry (***) . (f *** g)
and we're done as f ***' g returns a function taking two tuples and apply f and g separately to each component. This is good as we can rewrite prod as:
prod = liftM2 $ uncurry (***) . ((*) *** (zipWith (+)))
which is essentially a smart combination of functions. Notice that no arguments of prod has been specified: this is where point-free programming style really lies. Changing the way prod is written will change the type of its arguments, in single place, without requiring you to rewrite them in two places (i.e. the argument list).
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